How to calculate the size of a directory
Returns the filesize of a whole folder including all sub folders and files.
/** * Calculate the full size of a directory * * @author Jonas John * @version 0.2 * @link http://www.jonasjohn.de/snippets/php/dir-size.htm * @param string $DirectoryPath Directory path */ function CalcDirectorySize($DirectoryPath) { // I reccomend using a normalize_path function here // to make sure $DirectoryPath contains an ending slash // (-> http://www.jonasjohn.de/snippets/php/normalize-path.htm) // To display a good looking size you can use a readable_filesize // function. // (-> http://www.jonasjohn.de/snippets/php/readable-filesize.htm) $Size = 0; $Dir = opendir($DirectoryPath); if (!$Dir) return -1; while (($File = readdir($Dir)) !== false) { // Skip file pointers if ($File[0] == '.') continue; // Go recursive down, or add the file size if (is_dir($DirectoryPath . $File)) $Size += CalcDirectorySize($DirectoryPath . $File . DIRECTORY_SEPARATOR); else $Size += filesize($DirectoryPath . $File); } closedir($Dir); return $Size; }
Author:
Jonas John
License:
Public Domain
Language:
PHP
Created:
03/29/2006
Updated:
10/01/2007
Tags:
directory functions, files, size
Related links:
$SizeInBytes = CalcDirectorySize('data/');
Sorry folks, comments have been deactivated for now due to the large amount of spam.
Please try to post your questions or problems on a related programming board, a suitable mailing list, a programming chat-room,
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Older comments:
$size = 0;
if (is_dir($dir)) {
$objects = scandir($dir);
foreach ($objects as $object)
if ($object != "." && $object != ".." && $object != 'index.php')
if (filetype($dir."/".$object) == "dir")
$size += $this->dirsize($dir."/".$object);
else
$size += filesize($dir."/".$object);
reset($objects);
}
return $size;
}
Took me longer to debug than to write myself, man!
Thanks for your great snippets